(CH3SOCH2--Na+)
This is the classical analysis for establishing the linkage pattern of sugar residues. The method has several steps; conversion of the polysaccharide to the polyanion, methylation of all free alkoxy groups with methyl iodide, hydrolysis to monosaccharides, reduction to alditols and acetylation to give partially methylated alditol acetates (PMAAs). The three last steps are similar or identical to those in sugar analysis. The first alkylation step can be obtained in a variety of ways most of them relying on the dimsyl anion, CH3SOCH2-, and some on the hydroxide anion. Thus, the finding of a 2,3,4,6-tetra-O-methyl-hexose in a hydrolysate, detected as the 1,5-di-O-acetyl-2,3,4,6-tetra-O-methyl-hexitol derivative indicates a terminal hexose residue i.e. a 1-linked residue. Since position 5 is not methylated, the ring must be formed through that hydroxy group and the residue be pyranosidic i.e. have a 6-membered ring.
The presence of a 2,3,6-tri-O-methyl-hexose indicates either a 4-linked residue with a ring fused 1,5 i.e. a pyranosidic residue, or a 5-linked residue with a ring fused 1,4 i.e. a furanosidic residue. There are two ways to establish the presence of the possible furanosidic ring:
Acetamido sugars are normally methylated on the nitrogen to give the N-methyl-acetamido sugar. Occasionally the acetamido sugars is not quantitatively methylated and two peaks are obtained in the GLC chromatogram, one for the N-methylated and one for the unmethylated. Uronic acids give, after hydrolysis and treatment with sodium borohydride, the sodium salts of the acid and these are not volatile. One of the most common problems encountered with methylation analysis is undermethylation i.e. hydroxy groups are not converted to OMe groups but remain as OH-groups.